Factorise : 49a6 - 28a³b³+4b6

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Yogita Ingle 5 years, 1 month ago
{tex}49a^6 - 28a^3b^3 + 4b^6{/tex}
{tex}= (7a^3)^2 - 2(7a^3)(2b^3) + (2b^3)^2 ... (looks like (a-b)^2 = a^2 - 2ab + b^2){/tex}
{tex}= (7a^3 - 2b^3)^2{/tex}
2Thank You