The sum of three consecutive multiples …
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Yogita Ingle 5 years, 1 month ago
Let the first multiple of 8 be 8x.
Therefore the second consecutive multiple of 8 will be 8(x+1)
Also the third consecutive multiple of 8 will be 8(x+2).
It is given that the sum of these three consecutive multiples of 8 is 888
=> 8x + 8(x+1) + 8(x+2) = 888
=> 8x + 8x + 8 + 8x + 16 = 888
=> 24x + 24 = 888
Take 24 on the RHS
=> 24x = 888 - 24
=> x = 864/24
=> x = 36.
Therefore First multiple of 8 be 8x = 8 x 36 = 288
Second Multiple of 8 be 8(x + 1) = 8(36 + 1) = 8 x 37 = 296
Third Multiple of 8 be 8(x + 2) = 8(36 + 2) = 8 x 38 = 304
If we sum up these three multiples i.e (288 + 296 + 304) we get 888.
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