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Calculate the concentration of nitric acid …

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Calculate the concentration of nitric acid in moles per litre in a sample which has a density 1.41g ml and the mass percent of nitric acid in it being 69%

Posted by Mahi Chaudhary 4 years, 4 months ago

CBSE > Class 11 > Chemistry

1 answers

Gaurav Seth 4 years, 4 months ago

Given density of aqueous solution is 1.41 gm/ml of which 69% is nitric acid (HNO3).

So, 69% of 1.41 => 1.41 x 69/100 = 0.9729

Density of Nitric Acid = 0.9729 gm/ml

Now, Density = Mass/Volume. So,

0.9729 = Mass of HNO3/1000ml

Mass of HNO3 = 972.9 gm

No. of moles of HNO3 = Mass of HNO3/Molar mass of HNO3

= 972.9/63

= 15.44 mol.

So Molarity of HNO3 = No. of moles of HNO3/Volume of Solution

= 15.44/1 L

= 15.44 M

(Note) : We find molarity because in the question it is asked to moles per litre which is molarity(M).

1Thank You

ANSWER

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