. A rifle of mass 3 …
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Yogita Ingle 3 years, 11 months ago
We have,
Mass of the rifle, m₂ = 3 kg
Mass of the Bullet, m₁ = 0.03 kg
The velocity of the bullet, v₁ = 100 m/s
Time taken by bullet to move through the barrel, t = 0.003 s
So,
Initial velocity of rifle, u₂ = 0 m/s.
Initial velocity of bullet, u₁ = 0 m/s.
Final velocity of bullet, v₁ = 100 m/s.
Final velocity of rifle = v₂ m/s.
Now, we know from the law of conservation of momentum,
m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂
So,
(0.03 x 0) + (3 x 0) = (0.03 x 100) + (3 x v₂)
0 = 3 + 3.v₂
v₂ = -1 m/s
Therefore, acceleration of the rifle is given by,
So,
The Force experienced by rifle, therefore, would be,
F = m.a
F = 3.(-333.33)
F ≈ 1000 N
0Thank You