If 1g of Oxygen element contains …
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Gaurav Seth 3 years, 11 months ago
No. of Particles = given mass/Gram Atomic/Molecular Mass x Avogadro's Number
Gram atomic mass of oxygen = 16u (given)
Given mass = 1g
No. of atoms = 1/16 x 6.022 x 10²²
= 0.376375 x 10²² = 3.763 x 10²¹ atoms
So, X = 3.763 x 10²¹
Similarly, for aluminum,
No of atoms = 1/27 x 6.022 x 10²²
≈ 2.230 x 10²¹ atoms
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