If 1g of Oxygen element contains …
CBSE, JEE, NEET, CUET
Question Bank, Mock Tests, Exam Papers
NCERT Solutions, Sample Papers, Notes, Videos
Related Questions
Posted by Himanshi Sharma 1 year, 1 month ago
- 0 answers
Posted by Huda Fatima 1 year, 1 month ago
- 2 answers
Posted by Op Garg 1 year, 1 month ago
- 2 answers
Posted by Moksh Bhatia 1 year, 1 month ago
- 0 answers
Posted by Prasanna Mendon 1 month, 2 weeks ago
- 1 answers
Posted by Anmol Kumar 1 year, 1 month ago
- 0 answers
myCBSEguide
Trusted by 1 Crore+ Students
Test Generator
Create papers online. It's FREE.
CUET Mock Tests
75,000+ questions to practice only on myCBSEguide app
Gaurav Seth 4 years, 10 months ago
No. of Particles = given mass/Gram Atomic/Molecular Mass x Avogadro's Number
Gram atomic mass of oxygen = 16u (given)
Given mass = 1g
No. of atoms = 1/16 x 6.022 x 10²²
= 0.376375 x 10²² = 3.763 x 10²¹ atoms
So, X = 3.763 x 10²¹
Similarly, for aluminum,
No of atoms = 1/27 x 6.022 x 10²²
≈ 2.230 x 10²¹ atoms
1Thank You