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A train accelerates from 36 km/h …

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A train accelerates from 36 km/h to 54 km/h in 10 sec. (i) Acceleration (ii) The distance travelled by car.

Posted by Mishika Pandey 3 years, 11 months ago

CBSE > Class 09 > Science

3 answers

Piyush Kumar 3 years, 11 months ago

By the car ?

0Thank You

Neelesh Verma 3 years, 11 months ago

u=36km/h= 36×5÷18 =10 sec. v=54km/h=54×5÷18=15 sec. t=10 sec. a=v+u÷t=10+15÷10=11.5m/sec^2 2. v^2-u^2 =2as 15×15 -10×10 =2×11.5×s 125=2×11.5×s 125÷23=s s=5.43(approx

1Thank You

Taniya Chauhan 3 years, 11 months ago

1. u=36km/h= 36×5÷18 =10 sec. v=54km/h=54×5÷18=15 sec. t=10 sec. a=v+u÷t=10+15÷10=11.5m/sec^2 2. v^2-u^2 =2as 15×15 -10×10 =2×11.5×s 125=2×11.5×s 125÷23=s s=5.43(approx.)

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