No products in the cart.

Calculate the percentage of ionic character …

CBSE, JEE, NEET, CUET

CBSE, JEE, NEET, CUET

Question Bank, Mock Tests, Exam Papers

NCERT Solutions, Sample Papers, Notes, Videos

Calculate the percentage of ionic character for HF having bond length 0.83A and dipole moment 1.82D
  • 1 answers

Yogita Ingle 4 years, 5 months ago

 

To calculate % gornic character we consider 100 % iconic bond.

μ=Q×d

=(1.60×10−19C)×0.83×10−10m×(1D/ 3.336×10−30​)

% gonic character =1.82/3.980 ​×100

=45.70%

% covalent character = (100-% ginoc character)

=54.3%

http://mycbseguide.com/examin8/

Related Questions

74 g of calcium hydroxide Ca(OH)2 in 1 liter
  • 1 answers
How to calculate na2so4 mass percent with step by step
  • 0 answers

myCBSEguide App

myCBSEguide

Trusted by 1 Crore+ Students

Test Generator

Test Generator

Create papers online. It's FREE.

CUET Mock Tests

CUET Mock Tests

75,000+ questions to practice only on myCBSEguide app

Download myCBSEguide App