at 25°celsius and 760mm of mercury …
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Sia ? 4 years, 4 months ago
Given
P₁ = 760 mm
V₁ = 600 ml
T₁ = 25° C = 273 + 25 = 298 K
T₂ = 10° C = 273 + 10 = 283 K
V₂ = 640 ml
P₂ = ?
Using Combined Law of Gas,
P₁V₁/T₁ = P₂V₂/T₂
760 x 600/298 = P₂ x 640 / 283
P₂ = 760 x 600 x 283 / 298 x 640
P₂ = 676.6 mm
So the required pressure is 676.6 mm of Hg
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