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A bus is moving with the speed 30 m/s brought to rest within 10 sec by applying breaks. What is retardation and distance covered by the bus before coming to rest

Posted by Sirsa Kar 4 years ago

CBSE > Class 09 > Science

3 answers

Ashirwad Chauhan 4 years ago

Retardation is -3m/s² Distance is 150m

0Thank You

Aashna Jaiswal 4 years ago

u(initial velocity) =30m/s v(final velocity) =0m/s t(time) =10sec Find retardation? a=v-u/t a=0-30/10 a=-3m/s^2 It's mean that retardation is -3m/s^2 Find distance Use of second equation of motion to find distance S=ut+1/2at^2 S=30*10+1/2*(-3) *(10) ^2 S=300+(-150) S=300-150 S=150m It's mean that distance is 150m.

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Sarita Panda 4 years ago

Retardation -3m/s² and distance is 150m.

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