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a body starts from rest and accelerates to the speed of 5m/s in one second then the distance traveled it is

Posted by Gokul Settu 4 years ago

CBSE > Class 09 > Science

2 answers

Anmol Raushan 4 years ago

Initial velocity (u)- 0m/s Final velocity (v) - 5 m/s Time - 1 sec By 2nd equation of motion: s=ut + ½at²(a=5-0/1=5m/s²) s=0x1+½5x(1)²= 0+2.5x1=2.5m Distance is 2.5 m

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Anubhav Singh 4 years ago

Initial velocity(u) = 0m/s Final velocity(v) = 5m/s Time=1s Acceleration = v-u/t = 5m/s - 0m/s/1s = 5m/s/1s = 5m

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