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A a number consists of two digits digits whose sum is 9 if the digits are reversed the new number is 3 /8of the first number find the number

Posted by Pooja Kumari 5 years, 3 months ago

CBSE > Class 08 > Mathematics

3 answers

Jiya Wadhwa 5 years, 3 months ago

Let the no. is 10x + y x + y = 9 eq1 10y +x = 3/8 (10x +y) 80y + 8x = 30x + 3y 80y -3y = 30x - 8x 77y = 22x Now from eq1 put x = 9 - y 77y = 22(9 - y) 77y = 198 - 22y 99y = 198 y = 2 put y in eq1 x + y = 9 x + 2 = 9 x = 7 Number is 10x + y 10×7+2= 70 + 2 72 is the answer

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Tanu Shree 5 years, 3 months ago

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Aditya Pathania 5 years, 3 months ago

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CBSE > Class 08 > Mathematics