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Explain second equation of motion numerically

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Explain second equation of motion numerically
  • 1 answers

Yogita Ingle 4 years ago

Let the distance travelled by the object be “s”.

We know that,

→Distance = Average velocity × time

→Average velocity = (u+v)/2

Then s=(u+v)/2×t

According to first equation if motion,
v = u + at
substituting the value of v in above equation

s = (u+u+at)/2 x t

→s = (2u+at)/2 × t

→s = (2ut+at²)/2

→s = 2ut/2 + at²/2

→s=ut+1/2at²

Hence derived.

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