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Calulate mole frection of ethanol in …

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Calulate mole frection of ethanol in its 30 % aqueous solution

Posted by Vansh Thakur 5 years ago

CBSE > Class 11 > Chemistry

1 answers

Yachna Solanki 5 years ago

ANSWER let us assume , we have 100g solution. then, Solution of 30% NaOH means 30gm NaOH is present in 100g solution. Mass of WATER = 70 gm Moles of NaOH = 30/40 = 0.75 moles Moles of Water = 70/18 = 3.89 moles Mole frection of NaOH = xNaOH = 0.75/ 3.89 = 0.22

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