A bullet of mass 0.2 kg …
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Yogita Ingle 4 years, 1 month ago
Let the recoil velocity of gun be V.
Mass of gun Mgun=2.0 kg
Mass of bullet Mbullet=0.2 kg
Velocity of bullet Vbullet=150 m/s
Initial momentum of the system Pi=0
Applying the conservation of linear momentum : Pf=Pi
Or MgunV+MbulletVbullet=0
Or 2×V+0.2×150=0
2v +30=0
2v = -30
⟹ V=−15 m/s
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