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10. How many consecutive odd numbers …

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10. How many consecutive odd numbers will be needed to obtain 133? 11. Express 93 as the sum of consecutive odd numbers. 12. Write the prime factorisation of cube of 15.

Posted by Amulya Viii B - Aecs 5 years, 3 months ago

CBSE > Class 08 > Mathematics

1 answers

Yogita Ingle 5 years, 3 months ago

Let the seven consecutive odd integers be
(2x+1),(2x+3),(2x+5),(2x+7),(2x+9),(2x+11),(2x+13)
Then, (2x+1)+(2x+3)+(2x+5)+(2x+7)+(2x+9)+(2x+11)+(2x+13)=133
⇒14x+49=133
⇒14x=133−49=84
⇒x=1484=6
Hence, the least odd integer is =2x+1=2×6+1=13.

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