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A certain force exerted for 1.2s …

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A certain force exerted for 1.2s raises the speed of an object to 4.2m/s. Find its acceleration, if the mass of the object is 5.5 kg. Calculate the force applied.. Pls tell me the answer

Posted by Acbu Roy 4 years, 1 month ago

CBSE > Class 09 > Science

3 answers

Acbu Roy 4 years ago

Thanks for replying

1Thank You

Gaurav Seth 4 years, 1 month ago

Time = 1.2 second
Initial velocity = 1.8m/sec
Final velocity = 4.2m/sec

Now,
Acceleration = final v - initial v/time
So,

So,
Acceleration = 2m/sec²

Mass (given) = 5.5 kg
Now,

So,
F= 5.5 * 2 = 11N

1Thank You

Ram Sharma 4 years, 1 month ago

Flexibility in plants in due to

1Thank You

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