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Guys please help in this question ??? What is the sum of all interior angle of regular pentagon,hexagon,nonagon and 12sides of a polygon

Posted by Sajal Choudhary 5 years, 3 months ago

CBSE > Class 08 > Mathematics

1 answers

Bhavya Punia 5 years, 3 months ago

Sum of the interior angles of an n-sided polygon = (n−2)×180°n-2×180° (i) For a pentagon: n=5∴ (n−2)×180°=(5−2)×180°=3×180° = 540°n=5∴ n-2×180°=5-2×180°=3×180° = 540° (ii) For a hexagon: n=6∴ (n−2)×180°=(6−2)×180°=4×180° = 720°n=6∴ n-2×180°=6-2×180°=4×180° = 720° (iii) For a nonagon: n=9∴ (n−2)×180°=(9−2)×180°=7×180° = 1260°n=9∴ n-2×180°=9-2×180°=7×180° = 1260° (iv) For a polygon of 12 sides: n=12∴ (n−2)×180°=(12−2)×180°=10×180° = 1800

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