A hydrocarbon contains 85.7% C. If …
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Gaurav Seth 4 years, 10 months ago
Mass of Compound = 42 mg = 42 x 10-3 g
6.022 x 1023 molecules of compound = 1 mole
3.01 x 1020 molecules = (3.01 x 1020 ) / (6.022 x 1023 ) = 0.5 x 10-3 moles of compound
Molar mass of the compound = Mass /No. of moles = 42 x 10-3 g / 0.5 x 10-3 = 84 g/mol
Mass of Carbon in 1 mole of Compound = 85.7/100 x 84 g/mol = 71.98 = 72 g/ mol of C
Mass of H in 1 mole = (14.3/100) x 84 = 12.012g /mol of H
No. of C atoms = 72 / 12 = 6
No. of H atoms = 12.012 /1 = 12
Therefore the formula of the compound is C6H12.
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