Explain the conservation of momemtam deravation …

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When two object moving in same direction before collision the sum of initial momentum of two objects is equal to sum final momentum of same object after collusion. Suppose A and B moving with velocity Ua and Ub . Mass of A is Ma and mass of B is Mb. When A and B collide with each other then A exert force Fab on B and B exert Fba on B. After collision A move with velocity Va and B move with Vb velocity.Mass of A and B are same. Now rate of change of momentun of ball A=(MaVa--MaUa)÷t Similarly rate of change of momentun of ball B=(MbVb--MbUb)÷t According to second law of motion Fab =(MaVa--MaUa)÷t Also Fba= (MbVb--MbUb)÷ t According to third law of motion Fab=--Fba so ( MaVa--MaUa)÷t = (--MbVb--MbUb)÷t By solving this ??equation We get MaUa +MbUb = MaVa + MbVb Therefore sum of Intial momentun of A and B before collision is equal to sum of final momentum of A and B after collision. ????This is called conservation of momentum. Hope It is helpful to you??