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What volume of 10M HCL and …

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What volume of 10M HCL and 3M HCL should be mixed to obtain 1L of 6M HCL solution?....... !!?
  • 1 answers

Gaurav Seth 4 years, 3 months ago

Suppose volume of 10 M HCl required to prepare 1 L of 6 M HCl = x litre

 Volume of 3 M HCl required = (1-x) litre 

Applying molarity equation: 

Therefore Vol. of 10 M HCl required = 0.428 L = 428 mL. 

Vol. of 3 M HCl required = 1-0.428 = 0.527 L = 572 mL

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