What volume of 10M HCL and …

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Gaurav Seth 5 years, 4 months ago
Suppose volume of 10 M HCl required to prepare 1 L of 6 M HCl = x litre
Volume of 3 M HCl required = (1-x) litre
Applying molarity equation:
Therefore Vol. of 10 M HCl required = 0.428 L = 428 mL.
Vol. of 3 M HCl required = 1-0.428 = 0.527 L = 572 mL
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