Sum of the digits of a …

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Yogita Ingle 5 years, 4 months ago
Let ones place = x
Tens place = y
number will be = 10y +x
Number after reversing the digits = 10y +x
According to question:
x+y = 12 ⇒ x= 12- y ------(i)
(10y+x) -36 = 10x+y
⇒ 10y +x -10x-y =36 ⇒ 9y - 9x=36 ⇒ y-x=4 ----(ii)
Put the value of (i) in (ii)
y-(12-y)= 4 ⇒ y-12+y = 4 ⇒ 2y= 16 ⇒ y= 8 x= 4
Given number is 10y+x = 10 x 8+4 = 84
Hence, the number is 84
4Thank You