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Sum of the digits of a …

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Sum of the digits of a two - digit number is 12. The given number exceeds the number obtained by reversing the digits by 36. Find the number.
  • 1 answers

Yogita Ingle 5 years, 4 months ago

Let ones place = x

Tens place = y

number will be = 10y +x

Number after reversing the digits = 10y +x

According to question:

x+y = 12  ⇒ x= 12- y  ------(i)

(10y+x) -36 = 10x+y

⇒ 10y +x -10x-y =36  ⇒ 9y  - 9x=36 ⇒ y-x=4   ----(ii)

Put the value of (i) in (ii)

y-(12-y)= 4 ⇒ y-12+y = 4 ⇒ 2y= 16 ⇒ y= 8  x= 4

Given number is 10y+x = 10 x 8+4 = 84

Hence, the number is 84

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