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No.ov dagonall in a bexagon

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No.ov dagonall in a bexagon

Posted by Sankha Majhi 5 years, 4 months ago

CBSE > Class 08 > Mathematics

1 answers

Gaurav Seth 5 years, 4 months ago

Number of Diagonals = n(n-3)/2

This formula is simply formed by the combination of diagonals that each vertex sends to another vertex and then subtracting the total sides. In other words, an n-sided polygon has n-vertices which can be joined with each other in nC2 ways.

Now by subtracting n with nC2 ways, the formula obtained is n(n-3)/2.

For example, in a hexagon, the total sides are 6. So, the total diagonals will be 6(6-3)/2 = 9.

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CBSE > Class 08 > Mathematics