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Ones place digit of a two digit number is twice of the digit at tens place. If the new number obtained by reversing the digits of the number is greater by 18 than the number. Find the original two digit number.

Posted by Masum Patel 5 years, 4 months ago

CBSE > Class 08 > Mathematics

1 answers

Sajal Choudhary 5 years, 4 months ago

The answer is Let the two digits no. Be xy Then twice the tens digit number Like y=2x Then it makes 10x ➕ 2x =12x Then it will be reverse Yx =10y ➕ x =20x ➕ x =21 12x ➕ 21x =18 33x=18 X = 18 /33 Okkk

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CBSE > Class 08 > Mathematics