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Find the phythagorean triplet of A.6 …

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Find the phythagorean triplet of A.6 B.14
  • 1 answers

Yogita Ingle 5 years, 4 months ago

Pythagorean triplets:

For any natural number m > 1, we have (2m) ² + (m2 – 1)²= (m2 + 1)² . So, 2m, m² – 1 and m² + 1 forms a Pythagorean triplet.

I) Let  2m = 6
 m = 3

m²+ 1 = 3² + 1= 9 + 1 = 10

m²- 1 = 3 - 1 = 9 - 1 = 8

check:

6 ² + 8² = 36 + 64 = 100 = 10²

Hence, the triplet is 6, 8 & 10 

ii)

Let  2 m = 14

 m = 7

 m² + 1 = 7²+ 1 = 49 + 1 = 50

m²- 1 = 7² - 1 = 49 - 1 = 48

check:

14² + 48² = 196 + 1304 = 2500 = 50²

Hence, the triplet is 14, 48, and 50 

 

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