Sum of the digits of a …

CBSE, JEE, NEET, CUET
Question Bank, Mock Tests, Exam Papers
NCERT Solutions, Sample Papers, Notes, Videos
Related Questions
Posted by Arya Jain 1 year, 8 months ago
- 0 answers
Posted by Ojus Dimen 1 year, 8 months ago
- 1 answers
Posted by Jashan Preet 11 months, 1 week ago
- 1 answers
Posted by Monika 8B 9 months ago
- 0 answers
Posted by Madhav Sharma 1 year, 1 month ago
- 2 answers

myCBSEguide
Trusted by 1 Crore+ Students

Test Generator
Create papers online. It's FREE.

CUET Mock Tests
75,000+ questions to practice only on myCBSEguide app
myCBSEguide
Yogita Ingle 5 years, 8 months ago
Let the digits at tens place and ones place: x and 9−x respectively.
∴ original number =10x+(9−x)
=9x+9
Now Interchange the digits: Digit at ones place and tens place: x and 9−x respectively.
∴ New number: 10(9−x)+x
=90−10x+x
=90−9x
AS per the question
New number = Original number +27
90−9x=9x+9+27
90−9x=9x+36
18x=54
x=54/18
x=3
Digit at tens place ⇒3 and one's place : 6
0Thank You