Sum of the digits of a …
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Yogita Ingle 5 years, 5 months ago
The sum of the two digits is 9.
On interchanging the digits, the resulting new number is greater than the original number by 27.
Let us assume the digit of units place be x.
Then the digit of tens place will be 9-x.
Thus the two-digit number is 10(9-x) + x
Let us reverse the digit
the number becomes 10x + (9-x).
As per the given condition
10x + (9-x) = 10(9-x) + x + 27
= 9x + 9 = 90 – 10x + x + 27
= 9x + 9 = 117 – 9x
On rearranging the terms we get,
=18x = 108
x = 6
So the digit in units place is 6
Digit in tens place is 9-x= 9-6=3
Hence the number is 36
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