Three consecutive integers add up to …

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Posted by Kanishka Salukethakur 5 years, 5 months ago
- 4 answers
Gaurav Seth 5 years, 5 months ago
Let consecutive numbers be, x, x+1 and x+2.
According to the condition, we have
x + [x+1] +[x+2] =51
or x + x + 1 + x + 2 =51
or 3x + 3 = 51
Transposing 3 to RHS, we have
3x = 51 - 3 = 48
Dividing both sides by 3, we have:
or x =16
Now x + 1 = 16 + 1 = 17
and x + 2 = 16 + 2 =18
Thus, the required three consecutive numbers are: 16, 17 and 18.
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Sen Kathir 5 years, 5 months ago
0Thank You