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Calculate the mass of urea required …

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Calculate the mass of urea required in making 2.5kg of 0.25 molal solution. Guys please help me it's important?

    • Posted by Nayanika Mallick 4 years, 11 months ago

    CBSE > Class 11 > Chemistry
    • 1 answers

    ??Madhav Agrawal?? 4 years, 11 months ago

    Mass of solution-2.5 Kg.....De rakha Molality-0.25 m...De rakhi h.. Molar mass of urea--60 g mol−1 nikal lena... Mass of urea = Number of moles of urea × Molar mass of urea.......... Ese nikal aayega... Mass Of Urea... Mass of 0.25 moles of urea = 0.25 mol × 60 g mol⁻¹ = 15 g.... Ok... Mass of solution- 1000g+15g=1015 g. Ab.... 1015 g of aqueous solution contains urea = 15 g ∴ 2500 g of aqueous solution will require urea = 15 g / 1015 kg × 2500 g = 36.95 g = 37 g Mass of urea required in making 25 grams of 0.25m is 37 Gram............ .. .. .. .. Ok ....I think it will help you.....??

    2Thank You

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