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Derivation of secend law of motion

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Derivation of secend law of motion

Posted by Avinash Tripathi 4 years, 3 months ago

CBSE > Class 09 > Science

1 answers

Yogita Ingle 4 years, 3 months ago

Let us consider an object of mass m, moving along a straight line with an initial velocity u. Let us say, after a certain time t, with a constant acceleration, the final velocity becomes v.Here we see that, the initial momentum
p₁ = m  × u
The final momentum
p₂ = m  × v
The change in momentum can be written as
p₂ - p₁ = (m  ×v) - (m  ×u)= m (v-u)

As we know, the rate of change of momentum with respect to time is proportional to the applied force. The applied force
F∝ [m × (v-u)]/t
or

F∝ m × a
as acceleration (a) = rate of change of velocity with respect to time
.F= k × m × a

Above is the second law of motion formula.

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