The sum of three consecutive multiples …

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Yogita Ingle 5 years, 6 months ago
Let us take the first number as 11 (x – 1)
First consecutive number that is a multiple of 11 is 11x
Second consecutive number that is a multiple of 11 is 11(x + 1)
Therefore, the sum of 3 multiple of 11 numbers is 11x + 11(x – 1) + 11(x + 1) = 363
Now the sum of 3 numbers are 11x + 11(x – 1) + 11(x + 1) = 363
33x = 363; x = 33,
By substituting x = 33 in numbers 11x, 11(x – 1) and 11(x + 1) we get values 110, 121, 132.
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