A train starting from rest attains …
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Yogita Ingle 5 years, 3 months ago
Initial Velocity=u=0m/s
Final velocity= V= 72km/h
Time =5 min =5/60 h =1/12 h
acceleration=a=?
As we know that , a=v-u/t
⇒a=72-0/1/12
=72*12
=864km/h²
Distance travelled =s=ut+1/2at²
=0x1/12 +1/2(864)(1/12)²
=(1/2)x864x(1/144)
=3km
∴Distance travelled by the train for attaining this velocity 3km.
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