A train starting from a railway …
CBSE, JEE, NEET, CUET
Question Bank, Mock Tests, Exam Papers
NCERT Solutions, Sample Papers, Notes, Videos
Test
Related Questions
Posted by Yash Dwivedi 1 year, 4 months ago
- 3 answers
Posted by Moksh Bhatia 1 year, 4 months ago
- 0 answers
Posted by Huda Fatima 1 year, 4 months ago
- 2 answers
Posted by Anmol Kumar 1 year, 4 months ago
- 0 answers
Posted by Himanshi Sharma 1 year, 4 months ago
- 0 answers
Posted by Op Garg 1 year, 4 months ago
- 2 answers
Posted by Prasanna Mendon 4 months, 3 weeks ago
- 1 answers
myCBSEguide
Trusted by 1 Crore+ Students
Test Generator
Create papers online. It's FREE.
CUET Mock Tests
75,000+ questions to practice only on myCBSEguide app
Yogita Ingle 5 years, 6 months ago
Initial speed of the train, u = 0 km (Because train starts from the rest.
Final speed of the train, v = 40 km/h = \frac{5}{18} × 40 = 11.11 m/s.
Time taken to attain the speed = 10 minutes = 10 × 60 = 600 sec.
Acceleration of the train.
{tex}⇒ a=\frac{v-u}{t}{/tex}
Putting all the values, we get
{tex}⇒ a=\frac{v-u}{t}{/tex}
{tex}⇒ a=\frac{11.11-0}{600}{/tex}
{tex}⇒ a=\frac{11.11}{600}{/tex}
{tex}⇒ a=0.0185 \: m/s^2{/tex}
Hence, Acceleration of the train is 0.0185 m/s².
0Thank You