A train starting from a railway …
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Yogita Ingle 4 years, 4 months ago
Initial speed of the train, u = 0 km (Because train starts from the rest.
Final speed of the train, v = 40 km/h = \frac{5}{18} × 40 = 11.11 m/s.
Time taken to attain the speed = 10 minutes = 10 × 60 = 600 sec.
Acceleration of the train.
{tex}⇒ a=\frac{v-u}{t}{/tex}
Putting all the values, we get
{tex}⇒ a=\frac{v-u}{t}{/tex}
{tex}⇒ a=\frac{11.11-0}{600}{/tex}
{tex}⇒ a=\frac{11.11}{600}{/tex}
{tex}⇒ a=0.0185 \: m/s^2{/tex}
Hence, Acceleration of the train is 0.0185 m/s².
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