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how much CO2 is required to precipitate 10g caco3 from ca(oh)2

Posted by Palak Sindwani 5 years, 8 months ago

CBSE > Class 11 > Chemistry

1 answers

Rohit Krishna 5 years, 8 months ago

Ans:4.4g Ca(OH)2 + CO2 gives CaCO3 + H2O From stoichiometry,we can understand that '1 mole of Ca(OH)2 (molar mass:74g)' reacts with '1 mole of CO2 (molar mass :44g)' to give '1 mole each of CaCO3 and H2O. (molar mass:100g and 18g respectively)' Or,44g of CO2 gives 100g of CaCO3. Hence,to precipitate 1g of CaCO3, 44/100g=0.44g of CO2 is required. (Unitary method) Therefore, 10g of CaCO3 is obtained from 0.44*10=4.4g of CO2...

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