The sum of three consecutive multiples …

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- 1 answers
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Yogita Ingle 5 years, 8 months ago
Let the three consecutive multiples of 11 be 11x , 11(x + 1) and 11(x + 2)
11x + 11x + 11 + 11x + 22 = 363
33x = 363 - 33
33x = 330
so,
x = 10
hence,
the multiples are:
11x = 110
11(x+1)= 121
11( x + 2) = 132
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