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The value of kc = 4.24 …

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The value of kc = 4.24 at 800k for the reaction co + h2o = co2 + h2 Calculate equilibrium concentrations of co2,h2,co and h2o at 800k if only co and h2o are present initially at concentrations of 0.10M each

Posted by Karan Viras 5 years, 9 months ago

CBSE > Class 11 > Chemistry

1 answers

Mr. Singh 5 years, 9 months ago

CO(g) +H2O(g) =CO2(g) + H2(g) initially conc. 0.1M 0.1M 0 0 At eqm. (0.1-x)M (0.1-x)M xM xM x is a mole of each of product be formed. Applying Law of Chemical Equilibrium, Kc= [CO2][H2] / [CO][H2O] .........1 therefore, 4.24=x square / (0.1-x)square = x / 0.1-x = 2.06 OR x= 2.06(0.1-x) x= 0.206-2.06x 3.06x = 0.206 x= 0.206 / 3.06 = 0.067 therefore, [CO2]eq. = [H2]eq. = 0.067 M. [CO]eq. = [H2O]eq. = 0.1-0.067 = 0.033 M.

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