Show that the weight of the …
CBSE, JEE, NEET, CUET
Question Bank, Mock Tests, Exam Papers
NCERT Solutions, Sample Papers, Notes, Videos
Posted by Ujjwal Kant 4 years, 7 months ago
- 1 answers
Related Questions
Posted by Op Garg 2 months, 2 weeks ago
- 2 answers
Posted by Samir Chakma 1 month, 2 weeks ago
- 0 answers
Posted by Abhi Sandhu 2 months, 1 week ago
- 1 answers
Posted by Himanshi Sharma 2 months, 3 weeks ago
- 0 answers
Posted by Anmol Kumar 2 months, 2 weeks ago
- 0 answers
Posted by Yash Dwivedi 2 months, 3 weeks ago
- 3 answers
Posted by Prasanna Mendon 2 months, 2 weeks ago
- 1 answers
Posted by Huda Fatima 2 months, 2 weeks ago
- 2 answers
myCBSEguide
Trusted by 1 Crore+ Students
Test Generator
Create papers online. It's FREE.
CUET Mock Tests
75,000+ questions to practice only on myCBSEguide app
Meghna Thapar 4 years, 6 months ago
The weight of an object on the moon will be about one-sixth of what is on the earth. Thus, a spring balance which shows the weight of a body to be 6 N on earth will show a weight of only 1 N when taken to the moon. The weight of an object on the moon is less than that on the earth because the mass and radius of the moon are less than that of earth.
Suppose we have an object of mass m. let its weight on the moon be Wm, the mass of the moon is Mm and its radius is Rm. now, according to the universal law of gravitation, the weight of the object on the moon will be:
Wm = G x Mm x m/Rm2
Let the weight of the same object on the earth be We. The mass of the earth is M and its radius is R.
We = G x M x m/R2
Wm = G x 7.36 x 1022 kg x m / (1.74 x 106 m)2
Wm = 2.431 x 1010 G x m i.
We = 1.474 x 1011 G x m ii.
Dividing both the equations i. & ii.
Wm/We = 1/6
Weight of the object on the moon / Weight of the object on the earth = 1/6
Weight of the object on the moon = (1/6) × its weight on the earth.
0Thank You