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A bus is travelling at a speed of 72 km/h. Breaks are applied so as to produce a uniform acceleration of -0.4 m/s². Find how far the bus will go before it is brought to rest.

Posted by Vipasha Khatri 4 years, 7 months ago

CBSE > Class 09 > Science

1 answers

Jaskaran Saroya 4 years, 7 months ago

In here we put, 2as=v2-u2 So, 2×-0.4×s=(0)2-(20)2 (because it stops at last so final velicity will be zero and initial velocity is 72km/h is changes into 20m/s) -0.8×s=-400 S=-400/0.8 S=400×10/8 S=50×10 S=500m

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