Find the no. of aluminium ions …
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Yogita Ingle 5 years, 9 months ago
1 mole of aluminium oxide (Al2O3) = 2*27 + 3 * 16
= 102 g
i.e., 102 g of Al2O3 = 6.022 * 1023 molecules of Al2O3
Then, 0.051 g of Al2O3 contains =
= 3.011 * 1020 molecules of Al2O3
The number of aluminium ions (Al3+) present in one molecule of aluminium oxide is 2.
Therefore, the number of aluminium ions (Al3+) present in 3.011 * 1020 molecules (0.051 g ) of aluminium oxide (Al2O3) = 2 * 3.011 * 1020
= 6.022 * 1020
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