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A flooring tile has a shape of parallelogram whose base is 36cm and corresponding height is 10cm. How many tiles are required to cover a floor of area 1440 sq m?

Posted by Sudiksha Nema 5 years, 9 months ago

CBSE > Class 08 > Mathematics

1 answers

Anas Saifi 5 years, 9 months ago

36 cm= 0.36 m and 10 cm=0.1m area of parallelogram = base ×height 0.36×0.1= 0.036m^2 now we have to divide 1440m^2 by 0.036m^2 after dividing we get 40000 thus, 40000 tiles are needed

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CBSE > Class 08 > Mathematics