10 metre in 5 second 20 …
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Posted by Yash Kannojiya 5 years, 6 months ago
- 2 answers
Yogita Ingle 5 years, 6 months ago
\huge{\underline{Given:-}}
{tex}{d_1 = 10m ; t_1 = 5 seconds}{/tex}
{tex}{d_2 = 20m ; t_1 = 10 seconds}{/tex}
{tex}{d_1 = 30m ; t_1 = 10 seconds}{/tex}
By the formula of average speed
{tex}average \: speed = \frac{total \: distance \: travelled}{total \: time \: taken}{/tex}
Substituting the values.
{tex}average \: speed = \frac{10 + 20 + 30}{10 + 10 + 5}{/tex}
{tex}average \: speed = \frac{60}{25}{/tex}
{tex}average \: speed = 2.4 \: \frac{m}{s}{/tex}
{tex}\boxed{\boxed{average speed = 2.4 m/sec}}{/tex}
So,the average speed of the particle is 2.4 m/s.
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Md Faisal 5 years, 6 months ago
0Thank You