The perimeter of a trapeziumbis 52 …

CBSE, JEE, NEET, CUET
Question Bank, Mock Tests, Exam Papers
NCERT Solutions, Sample Papers, Notes, Videos
Posted by Jasmine Bhatra 5 years, 10 months ago
- 2 answers
Yogita Ingle 5 years, 10 months ago
Using Pythagoras' theorem, substitute in the values of the non-parallel side and the altitude:
10² = 8² - x²
x² = 36
x = 6
Therefore the base of the right-angled triangles is 6cm.
If we let the shorter parallel side of the trapezium = x, the longer parallel side will = x + 12.
P = x + x + 12 + 10 + 10 = 52
2x = 20
x = 10
Therefore the side lengths of the trapezium are 10, 10, 10 and 22.
A = h/2(a + b)
= 8/2 x 32
= 4 x 32
= 128cm²
Related Questions
Posted by Madhav Sharma 10 months, 1 week ago
- 2 answers
Posted by Ojus Dimen 1 year, 4 months ago
- 1 answers
Posted by Arya Jain 1 year, 4 months ago
- 0 answers
Posted by Monika 8B 5 months, 3 weeks ago
- 0 answers

myCBSEguide
Trusted by 1 Crore+ Students

Test Generator
Create papers online. It's FREE.

CUET Mock Tests
75,000+ questions to practice only on myCBSEguide app
myCBSEguide
Ashutosh Pathak 5 years, 10 months ago
0Thank You