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The perimeter of a trapeziumbis 52 …

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The perimeter of a trapeziumbis 52 cm and its non - parallel side is equal to 10 cm with its height 8 cm. Find its area.
  • 2 answers

Ashutosh Pathak 5 years, 10 months ago

128

Yogita Ingle 5 years, 10 months ago

Using Pythagoras' theorem, substitute in the values of the non-parallel side and the altitude:
10² = 8² - x²
x² = 36
x = 6

Therefore the base of the right-angled triangles is 6cm.

If we let the shorter parallel side of the trapezium = x, the longer parallel side will = x + 12.

P = x + x + 12 + 10 + 10 = 52
2x = 20
x = 10

Therefore the side lengths of the trapezium are 10, 10, 10 and 22.

A = h/2(a + b)
= 8/2 x 32
= 4 x 32
= 128cm²

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