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A force of 40N acts on …

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A force of 40N acts on an object at an angle of 45° with horizontal. As a result, the object is displaced horizontally through a distance of 14m. Calculate the work done by the force on the object.

    • Posted by Himanshu Singh 5 years, 8 months ago

    CBSE > Class 09 > Science
    • 2 answers

    Aman Kumar 5 years, 8 months ago

    Work done=F cos 45*s =40*14*0.52532198881 (0.52532198881=cos 45 degree) =560*0.52532198881 =294.180313738 J =294.18 J

    2Thank You

    Pradeep Tripathi 5 years, 8 months ago

    Himanshu the answer is 560 .the introduction of angle is just for confusing.work done =forse ×dosplacement.hense,40×14=560joule

    1Thank You

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