A scooter was bought at Rs.42,000 …

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Yogita Ingle 5 years, 11 months ago
Given:
Principal (P) =₹ 42,000, Rate of Interest (R) = 8%, Time (n) = 1 years
Amount (A) = P(1-R/100)^n
[Value depreciated]
A= 42000(1-8/100)¹
A=42000(1-2/25)
A= (42000×23)/25
A= 1680× 23
A= ₹ 38640
Hence, the value of the scooter after one year = ₹ 38640.
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