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(4y-5)^2 + 80y

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(4y-5)^2 + 80y

Posted by Indu Harjai 6 years, 2 months ago

CBSE > Class 08 > Mathematics

1 answers

Yogita Ingle 6 years, 2 months ago

(4y-5)² + 80y

= (4y)² - 2 (4y)5 + 5² + 80y

= 16y² - 40y + 25 + 80y

= 16y² - 40y + 25

2Thank You

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CBSE > Class 08 > Mathematics