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(4y-5)^2 + 80y

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(4y-5)^2 + 80y
  • 1 answers

Yogita Ingle 5 years, 11 months ago

(4y-5)2 + 80y

= (4y)2 - 2 (4y)5 + 52 + 80y

= 16y2 - 40y + 25 + 80y

= 16y2 - 40y + 25

 

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