A body is thrown vertically upwards …
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Yogita Ingle 5 years, 8 months ago
We have to initially find the Kinetic difference,
The formula for Kinetic difference is,
K.E{tex}=\frac{1}{2} \times m \times u^{2}{/tex}
{tex}=\frac{1}{2} \times 5 \times 10^{2}{/tex}
{tex}=\frac{1}{2} \times 5 \times 100{/tex}
{tex}=5 \times 50{/tex}
K.E = 250 \ J
The, Potential energy of the body is 250 J, when it reaches the highest point.
Loss in K.E = gain in P.E
→ P.E = 250 J
And the formula for potential difference is,
{tex}PE =m \times g \times h{/tex}
{tex}250=5 \times 10 \times h{/tex}
{tex}250=50 \times h{/tex}
{tex}h=\frac{250}{50}{/tex}
{tex}h = 5 \ m{/tex}
0Thank You