Calculate the work required to be …
CBSE, JEE, NEET, CUET
Question Bank, Mock Tests, Exam Papers
NCERT Solutions, Sample Papers, Notes, Videos
Posted by Mohd Bilal 5 years, 9 months ago
- 2 answers
Yogita Ingle 5 years, 9 months ago
Mass of car, m = 1500 kg
velocity, v = 60 km/h = {tex}60 \times \frac{5}{18}=16.67\ ms^{-1}{/tex}
Kinetic energy possessed by the car = {tex}\frac{1}{2} mv²{/tex}
⇒ KE = {tex}\frac{1}{2} \times 1500 \times 16.67^2=208416.7\ J=208.4\ kJ{/tex}
To stop the car, we have to make the KE of car 0. So the work need to be done is 204.4 kJ.
Related Questions
Posted by Himanshi Sharma 1 year, 1 month ago
- 0 answers
Posted by Huda Fatima 1 year, 1 month ago
- 2 answers
Posted by Op Garg 1 year, 1 month ago
- 2 answers
Posted by Anmol Kumar 1 year, 1 month ago
- 0 answers
Posted by Prasanna Mendon 2 months ago
- 1 answers
Posted by Moksh Bhatia 1 year, 2 months ago
- 0 answers
myCBSEguide
Trusted by 1 Crore+ Students
Test Generator
Create papers online. It's FREE.
CUET Mock Tests
75,000+ questions to practice only on myCBSEguide app
Bijaylaxmi Dash 5 years, 9 months ago
1Thank You