What is the work to be …
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Posted by Yash Sharma 5 years, 10 months ago
- 2 answers
Yogita Ingle 5 years, 10 months ago
Work = Change in kinetic energy
= 0.5 m (v² - u²)
= 0.5 × 1500 kg × [(60 × 5/18 m/s)² - (30 × 5/18 m/s)²]
= 156250 joules
= 156.25 kJ
Work done is 156.25 kJ
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Gaurav Kumar 5 years, 10 months ago
1Thank You