Sum of two digits of a …
CBSE, JEE, NEET, CUET
Question Bank, Mock Tests, Exam Papers
NCERT Solutions, Sample Papers, Notes, Videos
Test
Related Questions
Posted by Monika 8B 5 months, 3 weeks ago
- 0 answers
Posted by Madhav Sharma 10 months, 1 week ago
- 2 answers
Posted by Arya Jain 1 year, 4 months ago
- 0 answers
Posted by Ojus Dimen 1 year, 4 months ago
- 1 answers
myCBSEguide
Trusted by 1 Crore+ Students
Test Generator
Create papers online. It's FREE.
CUET Mock Tests
75,000+ questions to practice only on myCBSEguide app
Sia ? 6 years, 2 months ago
Let the units digit of the two-digit number be x.
Then, the tens digit of the two-digit number = 9 – x
[{tex}\because {/tex} Sum of the digits of the two-digit number 9]
∴ Original number = 10(9 – x) + x
= 90 – 10x + x
= 90 – 9x
When we interchange the digits, then
Units digit = 9 – x
and, tens digit
∴ Resulting number = 10x + (9 – x)
= 9x + 9
According to the question,
(9x + 9) = (90 – 9x) + 27
∴ 9x + 9x = 90 + 27 – 9. . . . [Transposing – 9x to L.H.S. and 9 to R.H.S.]
∴ 18x = 108
∴ {tex}x = \frac{{108}}{{18}}{/tex} . . . . [Dividing both sides by 18]
∴ x = 6
∴ 9 – x = 9 – 6 = 3 hence, the required two–digit number is 36.
Verification
3 + 6 = 9
63 = 36 + 27 hence, result verified.
1Thank You