Arif took a loan of rupees …
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Sia ? 6 years, 3 months ago
Compounded half yearly.
P = Rs. 80000
R = 10% per annum
{tex}\frac{{10}}{2}\% {/tex} per half year
{tex}n = 1\frac{1}{2}{/tex} years
{tex} = 1\frac{1}{2} \times 2{/tex} half years
= 3 half years
{tex}\therefore A = P{\left( {1 + \frac{R}{{100}}} \right)^n} = 80000{\left( {1 + \frac{5}{{100}}} \right)^3}{/tex}
{tex} = 80000{\left( {1 + \frac{1}{{20}}} \right)^3} = 80000{\left( {\frac{{21}}{{20}}} \right)^3}{/tex}
{tex} = 80000 \times \frac{{21}}{{20}} \times \frac{{21}}{{20}} \times \frac{{21}}{{20}}{/tex}
= Rs. 92610
This is the required amount
Difference in amounts = Rs. 92610 – Rs. 92400 = Rs. 210
Hence, the difference in amounts is Rs. 210.
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