The mass% of NaOh in 5 …
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Gaurav Seth 6 years, 3 months ago
1 mole NaOH is equivalent to 40 gm of NaOH.
Molality can be defined as the number of moles of solute in 1000 gm of solution.
Thus 5 molal aqueous NaOH solution contains, [ (5 x 40) = 200 ] gm NaOH.
Thus water present in the solution = (1000 - 200) = 800 gm
Moles of water present = (800 / 18) = 44.45
Thus the mole fraction of NaOH = (moles of NaOH / Total moles in solution) = (5 / 5 + 44.45) = 0.101
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